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1/ex2.c

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+#include <stdio.h>
+
+#define TEN 10
+#define ZERO 0
+//---------------------------------------------------------------------------------------
+//                                              Exercise 2
+//                                              ----------
+//
+// General : The program change order digits - reverse order.
+//
+// Input   : Number with 3 digits.
+//
+// Process : The program take the digits from right to left and multiplier the digit 
+//           by 10.
+//
+// Output  : Same number like input just reverse order.
+//
+//---------------------------------------------------------------------------------------
+// Programmer : Cohen Idan
+// Student No : None
+// Date       : 09.09.2019
+//---------------------------------------------------------------------------------------
+void main(void)
+{
+    short num,
+    temp,
+    result = ZERO;
+
+    printf("Enter number with 3 digits: ");
+    scanf("%hd", &num);
+
+    // Take the first digit from right to left and add to result
+    temp = num / TEN;
+    result += num - (temp * TEN);
+    num = temp;
+
+    temp = num / TEN;
+
+    // Multiplie the result by 10
+    result *= TEN;
+    result += num - (temp * TEN);
+    num = temp;
+
+    temp = num / TEN;
+    result *= TEN;
+    result += num - (temp * TEN);
+
+    printf("%hd\n", result);
+}